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Class 7 Maths Chapter 1 Exercise 1.2 Solutions

Get easy Class 7 Maths Chapter 1 Exercise 1.2 solutions with step-by-step answers for the +1000 and +10 button questions, including one lakh and number-of-presses problems.

Class 7 Maths Chapter 1 Exercise 1.2 Solutions

Students looking for Class 7 Maths Chapter 1 Exercise 1.2 Solutions can use this page to understand the questions based on the +1000 and +10 buttons.

These questions are designed to strengthen the idea of place value and help students understand how many thousands or tens are needed to make a particular number.

The key idea is very simple:

  • One press of the +1000 button adds 1,000.
  • One press of the +10 button adds 10.

So, instead of doing complicated calculations, we can divide the required number by the value added by one button press.


Question Information

Information Details
Class 7
Subject Mathematics
Book Ganita Prakash
Chapter 1 – Large Numbers Around Us
Exercise 1.2
Questions 1 and 2
Main Concept Place value, thousands and tens
Difficulty Easy

Question 1 — The Thoughtful Thousands

The Thoughtful Thousands has only a +1000 button.

How many times should the button be pressed to show the following numbers?

Key Idea

Every press adds:

1,0001,000

Therefore:

Number of presses=Required number1,000\text{Number of presses}=\frac{\text{Required number}}{1,000}

We can use this idea for every part.


(a) Three thousand

We need to make:

3,0003,000

Each press adds:

1,0001,000

Therefore:

3,000÷1,000=33,000\div1,000=3

Final Answer

The button should be pressed 3 times.


(b) 10,000

We need:

10,00010,000

Therefore:

10,000÷1,000=1010,000\div1,000=10

Final Answer

The button should be pressed 10 times.


(c) 53,000

We need:

53,00053,000

Therefore:

53,000÷1,000=5353,000\div1,000=53

Final Answer

The button should be pressed 53 times.


(d) 90,000

We need:

90,00090,000

Therefore:

90,000÷1,000=9090,000\div1,000=90

Final Answer

The button should be pressed 90 times.


(e) One lakh

We know:

1 lakh=1,00,0001\text{ lakh}=1,00,000

Therefore:

1,00,000÷1,000=1001,00,000\div1,000=100

Final Answer

The button should be pressed 100 times.

Why?

One press gives 1 thousand.

So 100 presses give:

100×1,000=1,00,000100\times1,000=1,00,000

which is one lakh.


(f) 153 times

The question gives the number of presses as:

153153

Each press adds 1,000.

Therefore:

153×1,000=1,53,000153\times1,000=1,53,000

Final Answer

153 presses show 1,53,000.


(g) How many thousands are required to make one lakh?

We know:

1 lakh=1,00,0001\text{ lakh}=1,00,000

and:

1 thousand=1,0001\text{ thousand}=1,000

Therefore:

1,00,000÷1,000=1001,00,000\div1,000=100

Final Answer

100 thousands\boxed{100\text{ thousands}}

are required to make one lakh.


Quick Table — Question 1

Required number / Presses Answer
3,000 3 presses
10,000 10 presses
53,000 53 presses
90,000 90 presses
1 lakh 100 presses
153 presses 1,53,000
1 lakh 100 thousands

Why Does the +1000 Button Work This Way?

The button adds exactly:

1,0001,000

every time.

For example:

1 press=1,0001\text{ press}=1,000 2 presses=2,0002\text{ presses}=2,000 3 presses=3,0003\text{ presses}=3,000

and so on.

Therefore:

n presses=n×1,000n\text{ presses}=n\times1,000

This is simply repeated addition.


Common Mistake in Question 1

Do not confuse 1,000 with 10,000 or 1,00,000.

Remember:

1 thousand=1,0001\text{ thousand}=1,000 10 thousand=10,00010\text{ thousand}=10,000 100 thousand=1,00,000=1 lakh100\text{ thousand}=1,00,000=1\text{ lakh}


Question 2 — The Tedious Tens

The Tedious Tens has only a +10 button.

How many times should it be pressed to show the given numbers?

Key Idea

Each press adds:

1010

Therefore:

Number of presses=Required number10\text{Number of presses}=\frac{\text{Required number}}{10}

Let’s solve each part.


(a) Five hundred

We need:

500500

Therefore:

500÷10=50500\div10=50

Final Answer

The button should be pressed 50 times.

Check:

50×10=50050\times10=500


(b) 780

We need:

780780

Therefore:

780÷10=78780\div10=78

Final Answer

The button should be pressed 78 times.

Check:

78×10=78078\times10=780


(c) 1,000

We need:

1,0001,000

Therefore:

1,000÷10=1001,000\div10=100

Final Answer

The button should be pressed 100 times.


(d) 3,700

We need:

3,7003,700

Therefore:

3,700÷10=3703,700\div10=370

Final Answer

The button should be pressed 370 times.


(e) 90,000

We need:

90,00090,000

Therefore:

90,000÷10=9,00090,000\div10=9,000

Final Answer

The button should be pressed 9,000 times.


(f) One lakh

We know:

1 lakh=1,00,0001\text{ lakh}=1,00,000

Therefore:

1,00,000÷10=10,0001,00,000\div10=10,000

Final Answer

The button should be pressed 10,000 times.

Check:

10,000×10=1,00,00010,000\times10=1,00,000


(g) 435 times

The question gives:

435 presses435\text{ presses}

Each press adds 10.

Therefore:

435×10=4,350435\times10=4,350

Final Answer

435 presses show 4,350.


Quick Table — Question 2

Required number / Presses Answer
500 50 presses
780 78 presses
1,000 100 presses
3,700 370 presses
90,000 9,000 presses
1 lakh 10,000 presses
435 presses 4,350

Why Does the +10 Button Work This Way?

Every press adds 10.

So:

1 press=101\text{ press}=10 2 presses=202\text{ presses}=20 10 presses=10010\text{ presses}=100 100 presses=1,000100\text{ presses}=1,000 1,000 presses=10,0001,000\text{ presses}=10,000

Therefore:

n presses=n×10n\text{ presses}=n\times10

If we know the target number and want to find the number of presses, we divide by 10.


Comparing the Two Buttons

The two questions show an important place-value relationship.

Button Value added in one press
+1000 1,000
+10 10

One press of the +1000 button adds:

1,000÷10=1001,000\div10=100

times as much as one press of the +10 button.

For example:

100×10=1,000100\times10=1,000

So 100 presses of +10 have the same numerical effect as 1 press of +1000.

This is a useful way to connect the question with place value.


A Simple Rule to Remember

For the +1000 button

To find the number of presses:

Target number÷1,000\boxed{\text{Target number}\div1,000}

To find the number displayed after a given number of presses:

Presses×1,000\boxed{\text{Presses}\times1,000}

For the +10 button

To find the number of presses:

Target number÷10\boxed{\text{Target number}\div10}

To find the number displayed after a given number of presses:

Presses×10\boxed{\text{Presses}\times10}


Why This Method Is Easy

There is no need for a complicated formula.

The button tells us exactly how much is added each time.

If the button adds 1,000, divide by 1,000 to find how many presses are needed.

If the button adds 10, divide by 10.

For the reverse question, simply multiply the number of presses by the amount added in each press.


Common Mistakes

Mistake 1: Dividing by the wrong number

For the +1000 button, divide by 1,000, not 100.

For the +10 button, divide by 10.

Mistake 2: Losing zeroes

For example:

1,00,000÷10=10,0001,00,000\div10=10,000

not 1,000.

Mistake 3: Confusing multiplication and division

  • Target number → number of presses: divide
  • Number of presses → displayed number: multiply

Key Concept for Revision

The entire exercise can be understood through two relationships:

Number shown=Number of presses×Value of one press\boxed{\text{Number shown}=\text{Number of presses}\times\text{Value of one press}}

and

Number of presses=Number shownValue of one press\boxed{\text{Number of presses}=\frac{\text{Number shown}}{\text{Value of one press}}}

These relationships help students solve similar questions quickly.


More Class 7 Maths Chapter 1 Resources

Suggested internal links for SyllabusStudy.in:

  • [Internal link: Class 7 Maths Chapter 1 Solutions]
  • [Internal link: Class 7 Maths Chapter 1 Notes]
  • [Internal link: Class 7 Maths Chapter 1 Important Questions]
  • [Internal link: Class 7 Maths Chapter 1 MCQs]
  • [Internal link: Class 7 Maths Chapter 1 Practice Questions]
  • [Internal link: Class 7 Maths Chapter 1 Practice Test]
  • [Internal link: Class 7 Maths Chapter-wise Solutions]

Exact URLs should be inserted only after those pages are published. No URLs have been invented.


PART B — PRACTICE QUESTIONS

Practice Question 1

A number machine has only a +500 button. How many times should the button be pressed to show:

  1. 2,500
  2. 8,000
  3. 25,000
  4. 1,00,000

Solution

Each press adds:

500500

1. For 2,500

2,500÷500=52,500\div500=5

So, 5 presses are needed.

2. For 8,000

8,000÷500=168,000\div500=16

So, 16 presses are needed.

3. For 25,000

25,000÷500=5025,000\div500=50

So, 50 presses are needed.

4. For 1,00,000

1,00,000÷500=2001,00,000\div500=200

So, 200 presses are needed.

Final Answers

5,  16,  50,  200\boxed{5,\;16,\;50,\;200}

presses respectively.

Explanation

We divide each target number by 500 because every press increases the displayed number by 500.


Practice Question 2

A number machine has only a +25 button.

  1. How many presses are needed to show 500?
  2. How many presses are needed to show 2,000?
  3. What number will appear after 125 presses?

Solution

Each press adds:

2525

1. To show 500

500÷25=20500\div25=20

Therefore, 20 presses are needed.

2. To show 2,000

2,000÷25=802,000\div25=80

Therefore, 80 presses are needed.

3. After 125 presses

Now we multiply:

125×25125\times25 =125×(100÷4)=125\times(100\div4) =3,125=3,125

Therefore, the number displayed is:

3,125\boxed{3,125}

Final Answers

  1. 20 presses
  2. 80 presses
  3. 3,125

Explanation

When the target number is known, divide by the amount added in one press. When the number of presses is known, multiply by the amount added each time.


PART C — REMEMBER

  1. One press of +1000 adds 1,000.
  2. One press of +10 adds 10.
  3. To find presses from a target number, divide by the value of one press.
  4. To find the displayed number from the number of presses, multiply.
  5. One lakh is:1,00,0001,00,000so it contains 100 thousands.

One-line trick

Target → Divide. Presses → Multiply.


Internal Links

  • Class 7 Maths Chapter 1 Solutions
  • Class 7 Maths Chapter 1 Notes
  • Class 7 Maths Chapter 1 Important Questions
  • Class 7 Maths Chapter 1 MCQs
  • Class 7 Maths Chapter 1 Practice Questions
  • Class 7 Maths Chapter 1 Practice Test
  • Class 7 Maths Chapter-wise Solutions

 

Rajesh Singh

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